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a所建模型的厚度与其长度和宽度相比很小,所以计算是基于有限厚度无限大平壁进行的。取图1所示模型的中纵截面,如图2所示,在t=0时刻,通入电流密度为J0的电流时,将在裂纹尖端(x0,y0,0)产生一功率密度为q的点热源,则在试件中某一点(x,y,z)在t时刻温度升高为: If modelling thickness the length and the width compare very slightly, therefore the computation is carries on based on the limited thickness infinitely great even wall.Takes shown in Figure 1 the model the longitudinal cross section, as shown in Figure 2, when the t=0 time, passes over the current [translate] 
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