青云英语翻译

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翻译结果1翻译结果2 翻译结果3翻译结果4翻译结果5

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证明。假设STC(G)≤3和g是不是平面的。库拉托夫斯基的定理(见[9]),G有作为拓扑未成年人的K5或K3,3。

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证据。猜想 stc(G)= 3 和 G 不是平坦的。从 Kuratowski 的 Theorem ( 明白例如(9)), G 像一个拓扑的次要机构一样有或者 K5 或者 3 岁的 K3。

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证明。假设 stc(G) ≤ 3 和 G 不是平面的。从库拉托夫斯基的定理 (例如见 [9]),G 的 K5 或 K3 3 作为拓扑的未成年人。

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正在翻译,请等待...

翻译结果5复制译文编辑译文朗读译文返回顶部

证明。 假设stc (G) ≤ 3和G不是平面的。 从Kuratowski的定理(看见即。 (9)), G有K5或K3,3作为一个拓扑学未成年人。
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aProof. Suppose stc(G) ≤ 3 and G is not planar. From Kuratowski’s Theorem (see e.g. [9]), G has either K5 or K3,3 as a topological minor. 证明。 假设stc (G) ≤ 3和G不是平面的。 从Kuratowski的定理(看见即。 (9)), G有K5或K3,3作为一个拓扑学未成年人。 [translate]